What must be the concentration of aqueous NH 3 which must be added to a solution containing 4 × 10 –3 M Ag + and 0.001 M NaCl, to prevent the precipitation of AgCl. Given that K sp (AgCl) = 1.8 × 10 –10 and the formation constant of [Ag(NH 3 ) 2 ] + is K formation = 
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Text Solution
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Silver ion concentration which can be allowed to remain in the solution,
1.8 ×10 –10 = [Ag + ] [Cl – ]
[Ag + ] = 
= 1.8 ×10 –7 M,
This quantity is so small that almost all the Ag + ion will be consumed by NH 3 in complex formation.
Ag + + 2NH 3 
[Ag(NH 3 ) 2 ] + K = 
t = 0 4 × 10 –3 b 0
at eq. 1.8 × 10 –7 (b – 8 × 10 –3 ) 4 × 10 –3
K = 
⇒ b = 0.0445 M.
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